Java get resource path. getResources() to find recursivly resources from my classpath? E. My doubt is not get a file in the resources folder (I now how to do this) but get the path to the resou 3. java I want to read the file in my resource folder in my Java project. Upon reading the Java docs instructions, if your resource is not in the same package as the class you are trying to access the resource from, then you have to give it relative path starting with '/'. getClass(). Class class is used to get the resource with the specified resource of this class. Resources are the collections of files or images or stuff of other formats. Explore examples, best practices, and troubleshooting tips. In this tutorial, we’ll learn how to read the path of the /src/test/resources directory. I'm using the features of Java 7 to read in a file. dir)。每种方法都适用于不同的场景，并给出了相应的示例。 This is a Resource implementation for java. access in abcManager. Explore tips, common mistakes, and best practices. General Information The PATH is the system variable that your operating system uses to locate needed executables from the command line or Terminal window. URLStreamHandler; /** A {@link URLStreamHandler} that handles resources on the classpath. . For that purpose I need an object of type Path. getResource () (or getResourceAsStream ()), Thread. I added this folder to the class path. getProperty()方法等。这些方法的核心是将应用程序的资源路径转化为可以被Java程序理解和访问的URL或者文件路径。 下面，我们将… 有时候想获取放在工程resources 文件下的文件路径，下面是几种方法： 1. How to access resources using the Path interface, and how to refactor your old-style File code to using Path. Learn how to get a path resource from a JAR file in Java with this comprehensive tutorial. properties and c:\my_projects\test-project 0 I have been searching for a way to get a file object from a file, in the resources folder. class. I would like to know the best way of loading a resource in Java: this. The code is the follo Learn how to find the path of the src/test/resources directory in JUnit tests with practical code examples and common pitfalls. In Java, accessing resources such as configuration files, images, and other external data is a common requirement in many applications. I don't want to load a file, I just want to know the path of the directory? Learn how to use ClassLoader. For example, we can load a file from any resource directory and will be then able to read the content of that file. json from the resources folder. This article will show you how to read a file from a `resources` folder, `getResourceAsStream` or `getResource`. How to load resources and files in Java. Learn how to obtain the absolute path of a file located in the resources folder of a Maven project using Java with step-by-step explanations and code examples. If resources are somewhere else they are ignored (this is default behavior which can be customized, we will explore that later). ) This utility function comes to the rescue! Javaでsrc/main/resourcesにあるファイルを読み込むのに少し手間取ったので備忘録です。 1. jar when the project is built, and I am starting to think that moving them outside the resource might be the only easy solution. Let's delete the previously created output Learn how to access and utilize resources within a JAR file in Java. Dec 30, 2025 · This guide demystifies loading files and directories from the Java resources directory using relative paths. war at build time. getResource (String)) as a java. If I wanted to load a certain File, I would use class. nio. file. src/test/resources Learn the correct way to use getResource () in Java to access resource files with best practices. getProperty (user. He had a different process to mark the resources root folder, but Java is Java so I figured the code to get at files in the resources root would be the same. I'm assuming the contents of src/main/resources/ is copied to WEB-INF/classes/ inside your . java class is located and put the serverConf. getResource ("/myFile. Java programs can use two mechanismsto access resources: Applets use Applet. getPath ();//获取文件路径 String fil Is there an API to get a classpath resource (e. Just note that the resources are not located in regular directories but inside the Jar so you need to access them via Class. point there is: directory from where you need to get config file must be in class path - not a file. getFile() But how can I get the full path to the src/test/resources directory, i. getClassLoader(). I have a maven module with the following directory structure and I want to get the path to abc. GitHub Gist: instantly share code, notes, and snippets. /resources/images/ as the path: java. Right now it fails the test. getResource、getClassLoader. csv and I want to load the file from a u Eclipse will also package these files along with your compiled code if you tell Eclipse to make jars. For example, given a One thing to keep in mind is that the relevant path here is the path relative to the file system location of your class in your case TestGameTable. getResource () Now, let’s see how we can get the resource using a Class instance. getResource()方法、使用Class. I used the following code for that MyClass. Discover common mistakes and solutions in our detailed guide! 文章浏览阅读3. The PATH system variable can be set using System Utility in control panel on Windows, or in your shell's startup file on Linux and Solaris. The files can be loaded from any folder or JAR file on your classpath. 文章浏览阅读10w+次，点赞12次，收藏68次。本文介绍了在Java中获取文件路径的四种不同方法，包括使用getClass (). 使用ClassLoader的getResource()方法 在Java中，可以使用ClassLoader的getResource()方法获取resources目 In a unit test I need to import a csv file. getResource ()、File类的getCanonicalPath ()和getAbsolutePath ()方法、以及System. The rules for searching resources associated with a given class are implemented by the class loader of the class. URLConnection; import java. The getResourceAsStream () method of java. 1. getResource("somefile"). 4. looking in the bootstrap directories in the JRE install path 文章浏览阅读6. Path handles, performing all operations and transformations via the Path API. The `getResource` method provides a powerful and flexible way to locate and load these resources. what is the best way to get the local file path of a ressource inside of my project? I have a lib folder containing the file dummy. getPath () method to get the path of the src/test/resources directory. What are the possible ways an absolute path of a file loaded via classpath can be deduced ? Java - Find Files in classpath under a Folder And SubFolder [Last Updated: Sep 24, 2020] Java Spring Framework This tutorial shows how to get the list of resources (files) from a classpath directory and subdirectory. This is my c The Main. public static Here is our complete Java program to load images, resources, text file or binary file from classpath in Java, resource can be anything, what is important is that it must be accessible. getResource与ClassLoader. io. Nov 4, 2025 · In this blog, we’ll demystify how Java resources work in JAR files, explain why common approaches break, and provide a step-by-step guide to correctly accessing resources—eliminating FileNotFoundException for good. . If you build your project with Maven, compiled classes and resources are in the /target directory in the project root folder. I have read a lot of similar questions on this website but non fix my problem exactly. I've tried numerous methods now, including FilenameUtils. With Maven or Gradle (or any build system that follows Maven’s source directory structure), put your resources in the src/main/resources directory, using the same path structure as in your src/main/java directory. class. Therefore obtaining a path to the resource is from the point of the compiled project. 在Java中，找到resource路径有多种方式，包括使用ClassLoader. This works (both in IDE and with the JAR) but this way I can't get a path to a file, only the file contents: ClassLoader classLoa created a new folder "resources" with all my images in eclipse. We can pass an absolute or relative path when locating a resource with a Class object. This guide demystifies loading files and directories from the Java resources directory using relative paths. Set Up Environment Variables: Add Bazel to your system path to run it from the terminal easily. getResourceAsStream() or so. 環境 JDK 17を使っています。 たぶん、多少バージョンが違っていても同じように動くと思います。 今回のフォルダ構造 今回はsrc/main/resources配下のファイルを取得したいとします。 $ tree . It is not related to the location of the TestGameTable. g. 34 I have this very specific need wherein a file is loaded from classpath and the same is used in another module which needs it's absolute path. Java examples of reading a file from the resources folder from a jar file, war file, spring application or the development environment. getResourceAsStream and I would b Is there a way in Java to construct a File instance on a resource retrieved from a jar through the classloader? My application uses some files from the jar (default) or from a filesystem directory. I need only the path to the folder, I do not want to read the files. My resources are html files I need to update and open in default browser. */ public class Handler extends URLStreamHandler { /** The classloader to find resources from. The getResource () method of java. Here are examples for both regular Java projects and Android projects: 本文介绍了Java中读取resources目录下文件路径的九种方法，包括根据文件路径读取内容、使用getResource和getPath方法、通过ClassPathResource类等获取文件流，以及利用绝对路径和环境变量获取文件位置，帮助开发者高效管理项目资源。 Steps to Compile TensorFlow Step 1: Install and Configure Bazel Download Bazel: Start by downloading and installing the version of Bazel compatible with your TensorFlow release. Java实现读取resources目录下的文件路径的九种方式 Java实现读取resources目录下的文件路径通常有以下九种方式： 1. net. A resource is file-like data with a path-like name, which resides in the classpath. if file location is c:\my_projects\test-project\config\my_config. It supports resolution as a File and as a URL and also implements the extended WritableResource interface. Resource loading in a Maven project Maven by default has a standard directory structure. finding all resources in the META-INF "directory": Imagine something like getClass(). 8w次，点赞40次，收藏194次。本文详述了九种在Java中读取项目资源文件的方法，包括使用getResource、getResourceAsStream、ClassPathResource等，特别适用于SpringBoot环境，解决了jar包内文件路径问题。 Java: Listing the contents of a resource directory The ClassLoader. 3w次，点赞15次，收藏76次。本文深入解析了Java中getResource和getResourceAsStream方法的使用，详细阐述了它们在不同路径情况下的行为，包括类相对路径和ClassPath根路径的区别。同时，对比了Class. I am trying to get a path to a Resource but I have had no luck. FileNotFoundException: . /resources/images/3g66l6his99h8pm (No such file or directory) writing to . This blog post will delve into the fundamental concepts of `getResource`, explore its usage methods, discuss common practices, and present best practices to help I am looking for a way to get a list of all resource names from a given classpath directory, something like a method List<String> getResourceNames (String directoryName). getResource () method to get the URL object of the resource of the class. (No, getResources () does not do it. The method returns the specified resource of this class in the form of InputStream object. Mar 17, 2024 · We might also have a file in src/test/resources with data for stubs that could be used by libraries like WireMock. xsd"). what I'd get from Class. Once I have a file in the resources root folder (or a folder inside of it) how do I get a path to that file? 文章浏览阅读8k次，点赞10次，收藏30次。本文深入探讨了Java中资源文件的加载方式，包括class. getResource () function can be a really handy way to load up your files in Java. Loading resources from the classpath is a common task in Java, and understanding how to do it properly is important for developing robust and efficient Java applications. Once you have secured an InputStream or URL towards the resource file- you can apply varying tactics when reading its contents; using a BufferedReader serves for text files. src |-main |-java |-org. I'm trying to find a way to get the absolute path for the resources folder in my junit test. xml there. getResources () for recursive resource retrieval in Java. Javaでは、ClassLoaderクラスのgetResource()メソッドを使用してリソースパスを取得できます。getResource()メソッドは、URLオブジェクトを返します。URLオブジェクトのgetPath( […] Learn how to properly access the resources folder in Java with expert tips and solutions to common issues. when you run your java application from command line you can set path to directory in -cp parameter or CLASSPATH system variable. getClass (). e. ルートからの絶対パスで取得 src/main/resources/sample1. getResource ("文件名"). getResource和getResourceAsStream的使用方法及区别，通过实例解释了如何从classpath根路径或当前类包路径正确读取配置文件。 Trying to get the path of a JSON file I have in my resource folder but failing to do so with getResource(). xyz |-init |- You cannot load the file directly like that, you need to use the resource abstraction (a resource could not only be in the file system, but on any place on the classpath - in a jar file or otherwise). This is located in the resources folder, i. java file is where this line of resource-calling code is contained. In Java, if you want to get the path of the resources directory programmatically, it depends on the type of project you're working on. Link already referred to how-to-get-a-path-to-a-resource-in-a-java-jar-file that got really close to answering my question: We know that we call the Class. 挨拶 どうも、はじめまして。 お久しぶりの方はお久しぶりです。ミツクマです🐻 今回は、Spring Bootのresourcesにあるファイルを取得する方法を書いていきます。 はじまり resourcesファイルに動画ファイルを設置して、Controllerから取得する 今天在Java程序中读取resources资源下的文件，由于对Java结构了解不透彻，遇到很多坑。正常在Java工程中读取某路径下的文件时，可以采用绝对路径和相对路径，绝对路径没什么好说的，相对路径，即相对于当前类的路径。在本地工程和服务器中读取文件的方式有所不同，以下图配置文件为例： （1 本文介绍6种Java公用打印文件方法，包括通过文件路径、getResource系列方法及ClassPathResource类获取文件内容并打印，在SpringBoot项目中有重要应用。 I have a resources folder/package in the root of my project, I "don't" want to load a certain File. The file path passed to the FileInputStream constructor should be an absolute path or a path relative to the current working directory. How can I use ClassLoader. I'm trying to read a file called jsonschema. java. getResource之间的联系与差异。 Javaでリソースディレクトリのパスを取得する方法を分かりやすく解説します。classpathからの取得方法や、jarファイル内のリソースアクセスについても説明。 In this article, we will learn how to retrieve the path of files or the directory itself from the /src/test/resources folder in JUnit tests using different approaches. In JUnit, you can use the getClass (). */ private final ClassLoader classLoader; public Handler() { Learn how to effectively access a folder within the Resources directory in Java with detailed steps and code examples. We’ll cover project structure, core methods for loading files, handling directories (even inside JARs), common pitfalls, and best practices. So let’s start with this method to resolve the full path of the corresponding JAR file finally. abc. Discover best practices and common mistakes. Implementing the byGetResource () Method Let’s first have a look at the implementation and then understand how it works: Explore effective Java methods for accessing files within your project's resources directory, including handling different contexts and build tools. However, the API disappointingly lacks a way to list all the files in the directory. This tutorial demonstrates how to get resource URL and read resource files in Java with the getResource() function. getResource (""). URL; import java. The method returns the specified resource of this class in the form of URL object. Now i tried to access this images URL url = new URL("imageA"); I also tried URL url = new Maven by default should copy all resources in "src/main/resources" to the root of the jar, so the directory should be empty. Path? Ideally, I'd like to use the fancy new Path APIs with classpath resources. location=data. exe which I want to execute but first I need to know where it is (Which can be different for each user, based on the install directory. When building an application, IntelliJ IDEA copies all resources into the output directory, preserving the directory structure of the resources relative to the source path. import java. getClassLoader (). getResource() 方法最简单，ClassLoader. Learn the best practices for configuring JUnit test resources directory paths in Java projects. Then inside class declare your location: The **resources directory** (standardized in build tools like Maven and Gradle) solves this by embedding resources into the classpath, allowing access via relative paths. Class. During build it only copies resources to '/target/classes' folder which were originally placed under src/main/resources directory. java file. getPath (); And I wanted to check the path of the file. and the system classloader will likely load resources from outside of your application's classpath, i. txt sample1 src/main/java/Foo. I've tried a few different ways but I can't get it to work. A resource is data (images, audio, text, and so on) that aprogram needs to access in a way that is independent of thelocation of the program code. So I guess I'm not using the resources root correctly. The FileInputStream objects can have memory and performance issues due to their use of finalizers. Examples Example resource directory structure D:\files-in-classpath-under-folder-and-subfolder>tree /a /f src/main/resources I get the following error when I use . In my code, I use the getResource() function to get the relative path (of type URL) to a file. Using Absolute Path of Resource To load a resource whose full path from the root of the jar file is known, use the full path starting with a “ / “. /" from linux to go up. My project has the following structure: /src/main/java/ /src/main/resources/ /src/test/java/ /src/test/resources/ I have a file in /src/test/resources/test. normalize() from commons IO, but I can't seem to be able to get a resource in another folder to get a Java FXML file. I want to write to the resources folder both in the production and test environment. Learn how to efficiently use Java's getResource () method to retrieve resources located in a parent directory, including detailed explanations and code snippets. I don't need to read them in the application but I need their path to open them in the browser. Learn how to get the file path of a resource in a Java JAR, along with common mistakes and debugging tips. Feb 8, 2025 · Explore different methods to obtain the path to a resource within a Java JAR file. If that is the case you can just do (substituting real values for the classname and the path being loaded). 本文介绍了 Java 运行时从 JAR 文件中获取资源的方法，其中 Class. getResource()方法、使用System. (e. But if you want to use the relative path as in your original code, you should create the config folder in the directory where the Main. In my specific case the resources are copied to a location at the same level as the enclosing package folder. The most common use of resources is bundling application images, sounds, and read-only data (such as default configuration). └── src └── main To get list of data from a src/main/resources/data folder: first of all mention your folder location in properties file as resourceLoader. I would like to get this URL in as robust a manner as possible. String fileName = this. lang. getResource() 方法更灵活，而 Get a Path to a Resource in a Java JAR File | Baeldung 最后修改: 2025年2月8日 by Diego Martin Java IO JAR Do you know any method to force him to use absolute path or to look for resources in resource filder or even use something like to use ". getPath(). I understand that the files are in a . getCodeBase()to get the base URL for the applet code and then extend the baseURL with a relative path to load the desired resou Learn how to effectively get the resource path in your application with clear steps and code examples. IOException; import java. currentThread I'm using Spring Boot and json-schema-validator. Java programs help us to load these files or images of the resources and perform a read and write operation on them. / writes to the project root folder. jndkk, a2sd2, mlgaz4, wozs, kan3yk, 5eeot, hoxsyw, 491wv3, fgxse, swv5,